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16=1024x^2
We move all terms to the left:
16-(1024x^2)=0
a = -1024; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-1024)·16
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{65536}=256$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-256}{2*-1024}=\frac{-256}{-2048} =1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+256}{2*-1024}=\frac{256}{-2048} =-1/8 $
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